Compound A (C7H10) reacts with one equivalent of Br2 in the dark at 0°C to give a single dibromide B (C7H10Br2) as a racemic mixture. Compound A rapidly decolorizes a solution of KMnO4. Ozonolysis of A (O3, then Me2S) produces a single dicarbonyl compound C (C7H10O2) which shows IR peaks at 1720 cm-1 and 1710 cm-1. The 1H NMR of C shows only three signals: a singlet at δ 2.1 (6H), a triplet at δ 2.5 (2H), and a triplet at δ 2.7 (2H). Propose a structure for A and a mechanism for the bromination.
Disconnect the cyclobutane ring into two alkene fragments. Consider how the substitution pattern on the starting materials will dictate the regiochemistry of the [2+2] addition. Problem 5: Sharpless Asymmetric Epoxidation (SAE) The Challenge:
Locate the reactivity centers in the target molecule.
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Play GreenPrint demo videoCompound A (C7H10) reacts with one equivalent of Br2 in the dark at 0°C to give a single dibromide B (C7H10Br2) as a racemic mixture. Compound A rapidly decolorizes a solution of KMnO4. Ozonolysis of A (O3, then Me2S) produces a single dicarbonyl compound C (C7H10O2) which shows IR peaks at 1720 cm-1 and 1710 cm-1. The 1H NMR of C shows only three signals: a singlet at δ 2.1 (6H), a triplet at δ 2.5 (2H), and a triplet at δ 2.7 (2H). Propose a structure for A and a mechanism for the bromination.
Disconnect the cyclobutane ring into two alkene fragments. Consider how the substitution pattern on the starting materials will dictate the regiochemistry of the [2+2] addition. Problem 5: Sharpless Asymmetric Epoxidation (SAE) The Challenge: advanced organic chemistry practice problems
Locate the reactivity centers in the target molecule. Compound A (C7H10) reacts with one equivalent of
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